Nemo kewayen rectangle: dabara da ayyuka

Ma'anoni na asali

Rectangle shi ne mai kusurwa huɗu wanda duk kusurwoyi daidai suke. Hakanan suna madaidaiciya kuma suna 90°.

Kewaye shine jimlar tsawon duk bangarorin polygon. Babban abin da aka yarda da shi shine babban harafin Latin P. A ƙarƙashin "P", yana da kyau a rubuta sunan adadi a cikin ƙananan haruffa don kada a ruɗe a cikin ayyukan da ke kan hanya. 

Idan an ba da tsayin bangarorin a cikin raka'a daban-daban, ba za mu iya gano kewayen rectangle ba. Don haka, don ingantaccen bayani, ya zama dole a canza duk bayanan zuwa raka'a ɗaya na ma'auni.

Menene kewayen da aka auna a ciki?

  • millimeter (mm);
  • santimita (cm);
  • dicimeter (dm);
  • mita (m);
  • kilomita (km) da sauran raka'o'in tsayi.

A cikin wannan ɗaba'ar, za mu yi la'akari da yadda za a lissafta kewayen rectangle da kuma nazarin misalan warware matsaloli.

Formula kewaye

Wurin (P) na rectangle daidai yake da jimillar tsawon duk sassansa.

P = a + b + a + b

Domin bangarorin wannan adadi daidai suke, ana iya wakilta dabarar kamar haka:

  • Gefe biyu: P = 2*(a+b)
  • Jimlar ƙima biyu na bangarorin: P = 2a+2b

Nemo kewayen rectangle: dabara da ayyuka

Gajeren gajere shine tsayi / nisa na rectangle, mafi tsayin gefe shine tushe / tsayinsa.

Misalan ayyuka

Aiki 1

Nemo kewayen rectangle idan ɓangarorinsa sun kasance 5 cm da 8 cm.

Yanke shawara:

Muna maye gurbin sanannun ƙimar u2bu5binto da dabara kuma sami: P u8d 26 * (XNUMX cm + XNUMX cm) uXNUMXd XNUMX cm.

Aiki 2

Matsakaicin yanki na rectangle shine 20 cm, kuma ɗayan bangarorinsa shine 4 cm. Nemo gefen na biyu na adadi.

Yanke shawara:

Kamar yadda muka sani, P=2a+2b. Bari mu ce 4 cm gefe ne а. Don haka bangaran da ba a sani ba b, ninka ta biyu, ana ƙididdige su kamar haka: 2b u2d P - 20a u2d 4 cm - 12 * XNUMX cm uXNUMXd XNUMX cm.

Saboda haka, gefen b = 12 cm / 2 = 6 cm.

Matsalolin matsala
Kuma yanzu yi!

1. Daya gefen rectangle yana da 9cm kuma ɗayan yana da 11cm tsayi. Yadda za a gano kewaye?
Ta yaya za mu yanke shawara:

Idan a = 9, to b = 9 + 11;
Sannan b = 20 cm;
Bari mu yi amfani da dabara P = 2 × (a + b);
P = 2 × (9 + 20);
Amsa: 58 cm.

2. Nemo kewayen rectangle tare da bangarorin 30 mm da 4 cm. Bayyana amsar ku cikin santimita.
Ta yaya za mu yanke shawara:

Maida 30mm zuwa cm:

30 mm = 3 cm.

Yi amfani da dabara don kewayen rectangle:

P \u003d 3 + 4 + 3 + 4 \u003d 14 cm.

Amsa: P = 14 cm.

3. Nemo kewayen triangle tare da tarnaƙi 2 a ciki da 300 mm. Bayyana amsar ku cikin santimita.
Ta yaya za mu yanke shawara:

Bari mu canza tsayin gefen zuwa santimita:

2 dm = 20 cm, 300 mm = 30 cm.

Nemo kewaye ta amfani da dabara P = 2 × (a + b):

P \u003d 2 × (20 + 30) \u003d 2 × 50 \u003d 100 (cm).

Amsa: P = 100 cm.

Menene kewayen Rectangle da yadda ake samunsa? #math #youtube #mathtrick #gajerun #ilmantarwa

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